Linear Programing

Vertices:	(0,0)		(0,6)		(6,0)
Constraints	Objective Function: C=3x+4y
x ≥ 0 y ≥ 0 x + y ≤ 6	3(0)+4(0)=0 Min	3(0)+4(6)=24 Max		3(6)+4(0)=18

Vertices:	(0,4)		(0,6)		(5,4)
Constraints	Objective Function: C=2x+5y
x≤5 y≥4 2x+5y≤30	2(0)+5(4)=20

Vertices:	(1,2)		(1,8)		(5,2)
Constraints	Objective Function: C=7x+3y
x ≥ 1 y ≥ 2 6x+4y ≤38	7(1,)+3(2)=13 Min	7(1)+3(8)=31		7(5)+3(2)=41 Max

Vertices:	(0,4)		(0,8)		(6,8)
Constraints	Objective Function: C=4x+6y
x ≥ 0 y ≥ 0 -2x+3y ≤ 12	4(0)+6(4)=24 Min	4(0)+6(8)=48		4(6)+6(8)=72 Max

Vertices:	(0,0) , (0,5)		(2,3) , (8,0)
Constraints	Objective Function: C=8x+7y
x ≥ 0 y ≥ 0 4x+4y≤20 x+2y≤8	8(0)+7(0)=0 8(0)+7(5)=35 0=Min	8(2)+7(3)=37 8(8)+7(0)=64 64=Max

Vertices:	(0,4)		(3,0)		(4,3)
Constraints	Objective Function: C=3x+5y
x ≥ 0 2x+3y≥6 3x-y≤9 x+4y≤16	3(0)+5(4)=20	3(3)+5(0)=9 Min		3(4)+5(3)=27 Max

Measures of central tendency

Bailey Vegter

Measures of central tendency:

Organizing and Displaying Data	Frequency and Histograms
Two Way Tables	Data Distributions

Graphing Exponential Equations

Exponential Equations:
Equation:

Y=a*b^x-h+k

Growth:
b>1

Decay:
0<b<1

Compound interest formula

Compound Interest Formula:

A=P(1+r/n)nt

A=Amount

P=Principal

r=Rate of interest

n=Rate of times per year, interest is compounded

nt=Time in years

Examples:

1. If you start a bank account with $10,000 and your bank compounds the interest quarterly at an interest rate of 8%, how much money do you have at the year's end ? (assume that you do not add or withdraw any money from the account)

Answer:

$10,824.32

2. The first credit card that you got charges 12.49 % interest to its customers and compounds that interest monthly. Within one day of getting your first credit card, you max out the credit limit by spending $1,200 . If you do not buy anything else on the card and you do not make any payments, how much money would you owe the company after 6 months?

Answer:

$12,77

(little bit of a highlighter problem lol)